Explore forming triangles with different combinations of side lengths.

✓ 1. Try to form a triangle by dragging

points A and D. Is it possible to form a

triangle with side lengths 1, 5, and 3

units? no

2. Is it possible to form a triangle with

side lengths 3, 4, and 5 units?

AB = 3 units

BC = 4 units

CD = 5 units

UUT

(A) No

(B) Yes

Step-by-step explanation:

(A) Using centimeters for example, it is not possible to create a closed or full triangle with side lengths 1cm, 5cm and 3cm. [See attachment for illustration]

(B) It is possible to create a triangle of side lengths 3cm, 4cm and 5cm. [See attachment also]

The Pythagoras Rule also applies in this case.

The sum of the squares of the lengths of the 2 shorter sides (the opposite side and the adjacent side) is equal to the square of the longest side (the hypotenuse).

(3×3) + (4×4) = (5×5)

9 + 16 = 25

1) No

2) Yes

3) No

4) Yes

5) Yes

Step-by-step explanation:

edge 2020:)

All correct

757764

step-by-step explanation:

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g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.