Fill in the missing information. Tim Worker is doing his budget. He discovers that the average miscellaneous expense is $45.00 with a standard deviation of $16.00. What percent of his expense in this category would he expect to fall between $38.60 and $57.80?

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

And replacing we got:

We can find the probability of interest using the normal standard table and with the following difference:

Step-by-step explanation:

Let X the random variable who represent the expense and we assume the following parameters:

And for this case we want to find the percent of his expense between 38.6 and 57.8 so we want this probability:

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

And replacing we got:

We can find the probability of interest using the normal standard table and with the following difference:

i belive those are the ones that are under 90 degreese.