Line A B has a negative slope and goes through points (negative m, p) and (w, z). Line A prime B prime has a positive slope and intersects with line A B. Which coordinate for points A' and B' would help prove that lines AB and A'B' are perpendicular? A': (p, m) and B': (z, w) A': (p, m) and B': (z, −w) A': (p, −m) and B': (z, w) A': (p, −m) and B': (z, −w)

(B)A': (p, m) and B': (z, −w)

Step-by-step explanation:

Line AB has a negative slope and goes through points (-m, p) and (w, z).

Line A'B' has a positive slope and intersects with line AB.

Definition: Two lines are perpendicular if the product of their slopes is -1.

Slope of AB

From the options, we consider the coordinates whole slope multiplied by the slope of AB gives a result of -1.

In Option B: A': (p, m) and B': (z, −w)

Slope of A'B'

The product of the slopes

Therefore, the coordinate for points A' and B' which would help prove that lines AB and A'B' are perpendicular is A': (p, m) and B': (z, −w).

You can try to calculate the slope of the others. They would not satisfy this condition.

answer: c. is your answer

step-by-step explanation: get me a black leather coat

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb