The 15th term of the linear sequence:
22, 18, 14, 10, 6

Step-by-step explanation:

For an nth term in an arithmetic sequence

U(n) = a + ( n - 1)d

where n is the number of terms

a is the first term

d is the common difference

From the above sequence

a = 22

d = 18 - 22 = 4

We are finding the 15th term so

n = 15

U(15) = 22 + (15-1)-4

= 22 + 14(-4)

= 22 - 56

The final answer is

Hope this helps you.