Question- choose the equation that represents the graph below A- Y= 3/4x+4
B- Y=-4/3x+4
C- Y=3/4x-4
D- Y=4/3x-4

B

Step-by-step explanation:

y = ax+ b

x=0 --> y =b =4

x=6 --> y= 6a+4 = -4 --> a= -4/3

so y = -4/3x +4

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐