Match the graph with the correct equation • y+2=(x-2)
•y+2= -(x-4)
•y+2= -(x+4)
•y-2= -(x-4)

y + 2 = -(x-4)

Step-by-step explanation:

Here, we want to match the graph with the correct equation

the equation is generally in the form

y = mx + c since it is a straight line

Let’s start with c which is the y- intercept

c = 2 from the graph

Let’s find value of the slope using the end points

The end points at top and at bottom are as follows respectively;

(-8,10) and (10,-8)

So the slope is ; y2-y1/x2-x1 and that is ;

-8-10/(10-(-8) = -18/18 = -1

So the complete form of the line would be;

y = -1(x) + 2

y = -x + 2

or simply y = 2-x

So which of the options fit this answer?

That would be;

y+ 2 = -(x-4)

This can be written as;

y + 2 = -x + 4

y = -x + 4-2

y = -x + 2

answer: the answer is b. i think hope i got it correct

step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.