Mathematics, 15.07.2020 23:01, andrew763

Write an equation for the following: a) The ellipse has foci (2, 0) and (–2, 0) and vertices (4, 0) and (–4, 0). b) The ellipse is centered at the origin, has axes of lengths 8 and 4, its major axis is horizontal.

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answered: chloeann4688

a) $\frac{x^2}{16} +\frac{ y^2}{12} = 1$

b) $\frac{x^2}{64} +\frac{ y^2}{16} = 1$

Step-by-step explanation:

The vertices are located in the x-axis, so we have a horizontal ellipse.

The equation of an ellipse is given by:

$\frac{(x - h)^2}{a^2} +\frac{ (y - k)^2}{b^2} = 1$

The coordinates of the foci and the vertices are given by:

Foci: $F(h \pm c, k)$

Vertices: $V(h\pm a, k)$

Comparing the coordinates with the values given, we have that:

h = 0, k = 0, c = 2, a = 4

To find the value of b we can use the following equation:

c^2 = a^2 - b^2

4 = 16 - b^2

b^2 =12

So the equation of the ellipse is:

$\frac{x^2}{16} +\frac{ y^2}{12} = 1$

If the ellipse is centered at the origin, we have:

h = 0, k = 0

The major axis is 'a' and the other axis is 'b', so we have:

a = 8, b = 4.

So the equation is:

$\frac{x^2}{64} +\frac{ y^2}{16} = 1$

answered: Guest

step-by-step explanation:

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answered: Guest

(2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

step-by-step explanation:

simplify the following:

x/x^2 + 3 x + 2 - (x (x + 1))/(x + 2)

combine powers. x/x^2 = x^(1 - 2):

x^(1 - 2) + 3 x + 2 - (x (x + 1))/(x + 2)

1 - 2 = -1:

x^(-1) + 3 x + 2 - (x (x + 1))/(x + 2)

put each term in 1/x + 3 x + 2 - (x (x + 1))/(x + 2) over the common denominator x (x + 2): 1/x + 3 x + 2 - (x (x + 1))/(x + 2) = (x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)):

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2))

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)) = ((x + 2) + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2)):

(2 + x + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

3 x^2 (x + 2) = 3 x^3 + 6 x^2:

(2 + x + 3 x^3 + 6 x^2 + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

2 x (x + 2) = 2 x^2 + 4 x:

(2 + x + 6 x^2 + 3 x^3 + 2 x^2 + 4 x - x^2 (x + 1))/(x (x + 2))

-x^2 (x + 1) = -x^2 - x^3:

(-x^2 - x^3 + 3 x^3 + 6 x^2 + 2 x^2 + 4 x + x + 2)/(x (x + 2))

grouping like terms, 3 x^3 - x^3 + 6 x^2 + 2 x^2 - x^2 + 4 x + x + 2 = (3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2:

((3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

3 x^3 - x^3 = 2 x^3:

(2 x^3 + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

6 x^2 + 2 x^2 - x^2 = 7 x^2: