Aram's four children are now 1, 5, 7, and 9 years old. In how many years will the sum of the ages of two of his children be twice the sum of the ages of the other two children?

In 2 years

Step-by-step explanation:

age right now 1,5,7,9

Let the number of years in which the sum of the ages of two of his children be twice the sum of the ages of the other two children=x

Therefore Age of the children after x years will be 1+x,5+x,7+x and 9+x

2[1+x + 5+x] = (7+x)+(9+x)

2[6+2x]= 7+9+x+x

12+4x=16+2x

4x-2x=16-12

2x=4

x=4/2=2

Let's verify if the answer is correct

-- Verify by substituting the value of x in this 2[1+x + 5+x] = (7+x)+(9+x)

2[1+2 + 5+2] = (7+2)+(9+2)

2[10]=9+11

20=20

Therefore 2 years is the answer

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: