Given the transition matrix P and the? initial-state matrix Upper S 0S0 ?below, find Upper P Superscript 4P4 and use Upper P Superscript 4P4 to find Upper S 4S4. A B Upper PPequals= A B left bracket Start 2 By 2 Matrix 1st Row 1st Column 0.8 2nd Column 0.2 2nd Row 1st Column 0.3 2nd Column 0.7 EndMatrix right bracket 0.8 0.2 0.3 0.7 ?; Upper S 0S0equals= left bracket Start 1 By 2 Matrix 1st Row 1st Column 0.1 2nd Column 0.9 EndMatrix right bracket

Step-by-step explanation:

First, we are to determine .

Therefore:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13