3. In the diagram O is the centre of the circle.
AOC is a straight line.
Angle BAO is 24° and Angle ADO is 42°
a)find angle CAD
b)find the size of ACB
c)find the size of angle BCD

Step-by-step explanation:

a) angle CAD= angle ODA ( in triangle OAD, OA=OD(same radius) angels opp                          to equal sides are equal)

hence angle CAD=42

b)angle b =90(angle subtended by diameter)

hence using angle sum property in triABC,

angle ACB=66eq4

c) in tri OAD,

Angle AOD=180-(42+42)(using angle sum prop.)

=> 96eq1

angleACD=1/2 Angle AOD ( angle subtende by an arc at centre is double the angle subtended...)

hence angle ACD =1/2 x 96(from eq1)

angleACD=48eq3

from eq 3,and eq4,

angle BCD= 48+66

=114 degree...

hope this helped youpls mark brainliest

a=r

d=q

c=p

b=s

hope this !

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!