a private opinion poll is conA private opinion poll is conducted for a politician to determine what proportion of the population favors decriminalizing marijuana possession. How large a sample is needed to be 92% confident that the sample proportion will not differ from the true proportion by more than 2% ducted for a politician to determine

1,914

Step-by-step explanation:

first we take down the information given to us

For 92% confidence, z = 1.75

Error of margin  E = 2% = 0.02

Since no estimate of population proportion has been given, we will assume:

p = q = 0.50

Hence,  

Sample size required n

n = ( z/E)² × p × q

n = ( 1.75/0.02)² × 0.5 × 0.5

n = (87.5)² × 0.5 ×0.5

n =  1914

aloha~! my name is zalgo and i am here to you out on this gracious day. in order to compare the ratios easily, it is best that we simplify the question first. so, the cougars would have 6 wins for 5 losses, bobcats make 2 wins for 1 loss. bulldogs and tigers have a ratio where you can't simplify it. so, the team with the lowest rate would be the bobcats.

i hope that this ! : d

"stay and stay proud! " - zalgo