Please help me i dont understand

∠ QPR = 40°

Step-by-step explanation:

∠ QPR + ∠ RPS = ∠ QPS, substitute values

7x - 9 + 4x + 22 = 90, that is

11x + 13 = 90 ( subtract 13 from both sides )

11x = 77 ( divide both sides by 11 )

x = 7

Thus

∠ QPR = 7x - 9 = 7(7) - 9 = 49 - 9 = 40°

40 degrees.

Step-by-step explanation:

Because segment PQ and segment PS are perpendicular, the angle they form is a right angle; a 90 degree angle.

We are trying to add angle QPR to angle RPS. They are complementary angles, since they form a 90 degree right angle.

(7x - 9) + (4x + 22) = 90

7x + 4x - 9 + 22 = 90

11x + 13 = 90

11x = 77

x = 7

Since x = 7 and angle QPR is 7x - 9, we can solve for its measure.

7 * 7 - 9 = 49 - 9 = 40.

Angle QPR measures 40 degrees.

Hope this helps!

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.