The water potential in one plant cell was calculated to be -4 bar. The water potential in another cell was found to be -11 bar. What was the difference in the water potential?

The difference in the water potential ∆P is 7 bar.

∆P = 7 bar

Step-by-step explanation:

Given;

The water potential in one plant cell was calculated to be -4 bar

P1 = -4 bar

The water potential in another cell was found to be -11 bar.

P2 = -11 bar

The difference in the water potential ∆P is;

∆P = P1 - P2

Substituting the given values;

∆P = -4 - (-11) bar

∆P = -4 +11 bar

∆P = 7 bar

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!