Solve these equations using elimination not substitution? 8x + 3y = 13 3x + 2y = 11 15 Points!

x = -1, y = 7

Step-by-step explanation:

8x + 3y = 13

3x + 2y = 11

Multiply the first equation by -2 and the second equation by 3. Then add them.

     -16x - 6y = -26

(+)     9x + 6y = 33

       -7x         = 7

x = -1

Now substitute x = -1 in the first original equation and solve for y.

8x + 3y = 13

8(-1) + 3y = 13

-8 + 3y = 13

3y = 21

y = 7

x = -1, y = 7

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4