Given f(x) = 3/2x - 4, solve for x (the input), when f(x) = 0 (the output is 0)

The input x = 8/3 results in a zero (0) function output.  

Step-by-step explanation:

Write f(x) = (3/2)x - 4 and set this equal to 0:   f(x) = (3/2)x - 4 = 0.  

Solve  (3/2)x - 4 = 0 for x by adding 4 to both sides:  (3/2)x = 4.

Finally, multiply both sides by the inverse of (3/2), to isolate x:

(2/3)(3/2)x = (2/3)4 = 8/3.

The input x = 8/3 results in a zero (0) function output.  

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.