Write an equation in point slope and slope intercept form of a line that passes through the given point and has the given slope m.(If possible please show work)

Point-Slope:

Slope-Intercept:

Step-by-step explanation:

The point-slope formula is . The slope-intercept formula is . Since we are given the point and slope, we can directly plug it into the point-slope formula.

Point-Slope

To find the slope-intercept form, we can manipulate the point-slope form to get the slope-intercept form.

Slope-Intercept

Point slope form   y+4= -1/2(x+3)  

Slope intercept form: y=-1/2x -11/2

Step-by-step explanation:

(-3,-4) : m= -1/2  

So we know the slope and to write it in point slope form it will be like ,

y- b = m(x-a)   Where b is the y value and a is the x value  and m in this case is the slope .

y- (-4) = -1/2 ( x-(-3)   which reduces to  y+4= -1/2(x+3)

Now to write it in slope intercept form  it will be  like y=mx+b and we kow htat m is the slope but we do not know b the y-intercept. But using the given coordinates we could plot it into the formula and solve for b.

y = mx +b

We  know that y is -4  

We know that m is -1/2  

we know that x is  -3  

so  -4 = -1/2(-3) + B

    -4  = 3/2 + b

   -3/2    -3/2

  b= -11/2  

We know now that the y intercept is -11/2 so we could write  it in slope intercept form.

y= -1/2x - 11/2

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq