What's the total surface area of a covered box with a length of 4 ft, a width of 3 ft, and a height of 6 ft? Question 17 options: A) 108 sq ft B) 38 sq ft C) 84 sq ft D) 96 sq ft

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A. 108 ft².

Step-by-step explanation:

Find the area of each face using the dimensions 4, 3 and 6. Remember, there are 6 total faces with 3 sets of congruent faces. The faces are rectangular, so the formula A = l × w will be used to solve for the area of each:

2(4 ·3) = 2(12) = 24 ft²

2(4· 6) = 2(24) = 48 ft²

2(3 · 6) = 2(18) = 36ft².

Add up the areas of the faces:

24 + 48 + 36 = 108 ft².

A) 108 sq ft

Step-by-step explanation:

SA = PH + 2LW

P = 2(L + W)

SA = 2(L + W)H + 2LW

SA = 2(4 ft + 3 ft)(6 ft) + 2(4 ft)(3 ft)

SA = 108 sq ft

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)