Letf(x)=log(x^2+1),g(x)=10-x^2 and R be the region bounded by the graphs of f and g, as shown above. a) Find the volume of the solid generated when R is revolved about the horizontal line y = 10. b) Region R is the base of a solid. For this solid, each cross section perpendicular to the x-axis is an isosceles right triangle with a leg in R. Find the volume of the solid. c) The horizontal line y = 1 divides region R into two regions such that the ratio of the area of the larger region to the area of the smaller region is k:1. Find the value of k.

its d. the first coordintaes are 10,32

step-by-step explanation:

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answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

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