Find the number of 4-digit numbers that contain at least three odd digits.

3000

Step-by-step explanation:

First find the 4 digit numbers that have all odd digits

Possible Odd digits  =5(1,3,5,7,9)  

So, total number of 4 digit numbers with odd digits can be calculated as  =5×5×5×5=625

Now find all the 4 digits numbers with at least 3 odd digits and the first digit as either 2,4,6,8 ( 0 would make it a 3 digit number)

The first digit can be 2,4,6,8

=4×5×5×5=500

Now find all the 4 digits numbers with at least 3 odd digits and the second digit as either 0,2,4,6,8

=5×5×5×5=625

Now find all the 4 digits numbers with at least 3 odd digits and the third digit as either 0,2,4,6,8

Now find all the 4 digits numbers with at least 3 odd digits and the second digit as either 0,2,4,6,8

=5×5×5×5=625

Now find all the 4 digits numbers with at least 3 odd digits and the fourth digit as either 0,2,4,6,8

=5×5×5×5=625

Add them together

625+500+625+625+625=3000

c-4 is the final answer! : )

1 3 5

step-by-step explanation:

i took the test: )