Competitive Diver Franco and Grace are competitive divers. Grace dives from a 20-meter cliff into the water, with an initial upward speed of 3.2 m/s. Franco dives from a springboard that is 10 meters above the water surface with an initial upward speed of 4.2 m/s. c. Graph both functions on the same graph. Label each function. d. What are the domain and range of each function in terms of the situation? Explain. Round values to the nearest tenth. e. Compare the maximum heights and the time that elapses before each diver hits the water. Project format: 1. Create a poster. You can use any size poster available to you. If your poster is large, you can always take a photo of it and send to your teacher. 2. Write a story that includes the answers. 3. Make a PowerPoint presentation 4. Create a drawing and include your answers in a creative way 5. Create a skit or play or song to go along with your answers 6. Be creative- If you can think of another format that you want to use for this project. Work with your teacher. Be sure your project format addresses all the questions listed above in the project description. Don’t forget to write your name and course and lesson number on the project.

the answers c

answer: -8.2562234e+13

d

step-by-step explanation:

hello and welcome!

so, when we see the words "proportional" along with a table, we need to know that we're looking numbers that divide by the same thing.

looking at this table, we simply have to do a trial and error, and divide to see which numbers have the same quotient. if you look at choice a & c, they both have equal quotients for three of the numbers, with one exception, so those can't be the answer. looking at b, there is no similarity, so that can't be it. then, we see d; if you divide all the numbers in the table, you'll see that they all divide by two, which is a proportional relationship, and our answer!

also, always remember that the x will always be the number that goes into y, and somewhere behind this table, is a formula. for this specific table, the formula would be:

since our x-value is being divided by two to get the y-value. and if they were to ask for more numbers in the series, this is the formula you would use to find them.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!