2/3 - 5bx = bx + 1/3 In the equation shown above, b is a constant. For what value of b = NO SOLUTIONS? A. 5 B. 0 C. -5 D. 2/5

B

Step-by-step explanation:

Here, we want to know at what values of b does the equation becomes not solvable

Now looking at the left hand side, we have;

2/(3-5bx) and also the right hand side bx + 1/3

For this expression if we insert b = 0, then automatically x cancels out on both sides of the equation and we shall be left with nothing to solve

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?