Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him ₹ 50 per metre and trousers material that costs him ₹ 90 per metre. For every 3 metres of the shirt material, he buys 2 metres of the trouser material. He sells the materials at 12% and 10% profit respectively. His total sale is ₹ 36,600. How much trouser material did he buy? PLease i want it with step by step explanation

Step-by-step explanation:

Let x represent the number of meters of shirt material that he bought.

Let y represent the number of meters of trouser material that he bought.

For every 3 metres of the shirt material, he buys 2 metres of the trouser material. It means that

2x = 3y

x = 3y/2

shirt material cost him ₹ 50 per metre and trousers material cost him ₹ 90 per metre. It means that the total cost is

50x + 90y

Selling price for the shirt material is

50x + (12/100 × 50x) = 56x

Selling price for the trouser material is

90y + (10/100 × 90y) = 99y

If his total sale is ₹ 36,600, it means that

56x + 99y = 36600- - - - - - - - 1

Substituting x = 3y/2 into equation 1, it becomes

56(3y/2) + 99y = 36600

Multiplying both sides by 2, it becomes

168y + 198y = 73200

366y = 73200

y = 73200/366

y = 200

x = 3y/2 = 3 × 200/2

x = 300

He bought 200 meters of trouser material

x+y = 29, 5x + 2y = 100

step-by-step explanation:

i'm guessing it was a multiple first option was the correct answer

42

step-by-step explanation:

256/6=42