Find the perimeter and the area of the LED screen of the camera. (Simplify your answer completely.) perimeter units area square units 4/x+6 long 3/x-1 wide

Step-by-step explanation:

The LED screen of the camera is rectangular in shape.

Given the length of the screen = 4/x+6

Width of the screen = 3/x-1

Area of the LED screen = Length * Width = 4/x+6 * 3/x-1

On simplification, Area = 12/(X+6)(X-1)

= 12/x²-x+6x-6

= 12/x²+5x-6 units²

Perimeter of the LED screen = 2(L+W)

= 2(4/x+6 + 3/x-1)

= 2(4(x-1)+3(x+6)/x+6(x-1))

= 2(4x-4+3x+18/x²+5x-6)

= 2(7x+14/x²+5x-6)

= 14(x+2)/x²+5x-6 units

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841