Which identity resulted from the proof in part A, which showed that a triangle with side lengths x2 − 1, 2x, and x2 + 1 is a right triangle? a. (x^2 − 1)^2 − (2x)^2 = (x^2 + 1)^2 b. -(x^2 − 1)^2 + (2x)^2 = (x^2 + 1)^2 c. (x^2 − 1)^2 + (2x)^2 = (x^2 + 1)^2 d. (x^2 − 1)^2 + (2x)^2 = -(x^2 + 1)^2

c.

step-by-step explanation:

simple you would first have to get   a negative number where as 1 to be multiplied by 24 and then you would have to multiply 6 time 4 and then repeat that process until you reach your term

answer: the answer to this problem is 2x and 2-x both have x as well as 2

step-by-step explanation: first you have to see what is the closest thing they have similar second you note it example 4x and 4+x they both have x and 4

the answer is b

step-by-step explanation: