A restaurant offers 6 choices of appetizer, 8 choices of main meal, and 5 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses. Assuming all choices are available, how many different possible meals does the restaurant offer? help I make brainless to the right answer

377 possible meals

Step-by-step explanation:

Let's split this up into 3 cases: one course, two courses, and three courses.

Case 1:

The customer only eats one course. If so, that means they only eat an appetizer, a main meal, or a dessert. There are 6 choices of an appetizer, 8 for a main meal, and 5 for a dessert. Add these together:

6 + 8 + 5 = 19

Case 2:

The customer will eat two courses. If so, that means they eat:

- appetizer + main meal

There are 6 choices for appetizer and 8 for main meal, so in total, there are 6 * 8 = 48 choices.

- appetizer + dessert

There are 6 choices for appetizer and 5 for dessert, so in total, there are 6 * 5 = 30 choices.

- main meal + dessert

There are 8 choices for the main meal and 5 for dessert, so in total, there are 8 * 5 = 40 choices.

So, if the customer eats 2 courses, they have 48 + 30 + 40  = 118 choices.

Case 3:

The customer will eat three courses.

Since there are 6 choices for an appetizer, 8 for a main meal, and 5 for dessert, we multiply them together to get:

6 * 8 * 5 = 240 total choices

Finally add all the total choices from each of the 3 cases:

19 + 118 + 240 = 377 possible meals

~ an aesthetics lover

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8