On a coordinate plane, a curved line with minimum values of (negative 1.56, negative 6) and (3, 0), and a maximum value of (1.2, 2.9), crosses the x-axis at (negative 2.5, 0), (0, 0), and (3, 0), and crosses the y-axis at (0, 0). Which interval for the graphed function has a local minimum of 0? [–3, –2] [–2, 0] [1, 2] [

Question:

On a coordinate plane, a curved line with

minimum values

o   (negative 1.56, negative 6)

o   (3, 0),

maximum value

o  (1.2, 2.9),

crosses the x-axis

o   (negative 2.5, 0),

o   (0, 0),

o   (3, 0),

crosses the y-axis

o   (0, 0).

Which interval for the graphed function has a local minimum of 0?

[–3, –2]

[–2, 0]

[1, 2]

[2,3]

Step-by-step explanation:

From the given information, it 'crosses' the x-axis at (3,0), and this is also a minimum.  Thus the local minimum is at (3,0), so the answer choice for the interval is [2,3]  (not indicated in the posted question, so double check).

the answer is -6

step-by-step explanation:

the answer is -6 because its next to the variable m

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6: 4= 3/2

18: 8= 9/4

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