You have in your pocket 10 coins.9 of them are ordinary coins with one tail and one head and the 10th coin has two heads. You randomly pick one coin from your pocket. What is the probability that this coin will land on heads? A. 0.45 B. 0.48 C. 0.55 D. 0.52 PLZ EXPLAIN, PLZ HELP!!!

C. 0.55

Step-by-step explanation:

You have 9/10 fair coins and 1/10 double heads.

The probability of throwing a head is (9/10*1/2)+(1/10*2/2)

=11/20 which is equal to 0.55

HOPES THIS HELP

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~