If one quart of paint is exactly enough for two coats of paint on a 9-foot by 10-foot wall, how many quarts of paint are needed to apply one coat of paint to a 10-foot by 12-foot wall? Express your answer as a common fraction.

2/3

Step-by-step explanation:

We are told in the question that

If one quart of paint is exactly enough for two coats of paint on a 9-foot by 10-foot wall

9 foot by 10 foot wall = an area of 9 × 10 = 90ft² × 2 coats of paint = 1 quart of paint

We are to find how many quarts of paint are needed

how many quarts of paint are needed to apply one coat of paint to a 10-foot by 12-foot wall .

10 × 12 = 120ft² × 1 coat of paint = x quart

Mathematically, if

One quart of paint = 90ft² × 2

x quart of paint = 120ft² × 1

Cross multiply

90ft²× 2 × x = 120ft²

x = 120/180

x = 2/3 quart of paint

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

step-by-step :