Suppose that the sitting back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 23.3 in. and a standard deviation of sigma equals 1.2 in. These data are often used in the design of different seats, including aircraft seats, train seats, theater seats, and classroom seats. Instead of using 0.05 for identifying significant values, use the criteria that a value x is significantly high if P(x or greater)less than or equals0.01 and a value is significantly low if P(x or less)less than or equals0.01. Find the back-to-knee lengths separating significant values from those that are not significant. Using these criteria, is a back-to-knee length of 25.6 in. significantly high?

The back-to-knee lengths separating significant values from those that are not significant are 20.2 in. and 26.4 in.

Using these criteria, a back-to-knee length of 25.6 in. is not significantly high, as is within the not-significant values.

Step-by-step explanation:

We have a normal distribution for the sitting back-to-knee length with mean 23.3 in. and standard deviation 1.2 in.

We have to calculate the critical values that limit the 1% right tail and 1% left tail.

This can be done looking for a standard normal distribution table for the values that satisfy:

This values for z are z=±2.576.

Then, we can calculate the bounds for our sitting back-to-knee length distribution as:

the correct answer is the second option

10.416 meters per second

step-by-step explanation:

distance=1 00 meters

time= 9.6 seconds in decimal form or 9 3/5 as a mixed number

average speed= 100/9.6

=10.416 meters per second or 10 52/125 as a mixed number.