Q3. A student plans a method to prepare pure crystals of copper sulfate. The student's method is
1. Add one spatula of calcium carbonate to dilute hydrochloric acid in a beaker.
2. When the fizzing stops, heat the solution with a bunsen burner until all the liquid is gone.
The method contains several errors and does not produce copper sulfate crystals.
5
Explain the improvements the student should make to the method so that pure crystals of
copper sulfate are produced. (6) * S

The reactants in this reaction ought to have been copper carbonate and sulfuric acid.

The student is trying to carry out a reaction that would produce copper sulfate using two starting materials. The process is also expected to involve the evolution if a gas. However the process failed to produce the desired product. The following adjustments should be made to the process;

If these two adjustments are made, the equation of the reaction occurs as follows; CuCO3(s) + H2SO(aq) → CuSO4(aq) + CO2(g) + H2O(l).

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1) The student didn't add copper sulfate but instead he added calcium carbonate.

2) The heated solution should be left to get bigger crystals and should not be instantly allowed to evaporate.

3) He should use copper carbonate not calcium carbonate.

4) Sulfuric acid was added instead of hydrochloric acid.

5) Add solid excessively so that all of the acid is retained.

6) Filter the solution to remove unreacted solid.

7) Heat gently, so the crystals will start to appear.

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step-by-step explanation:

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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