Please help within 30ish minutes I’m be g g in g you

x - 2y = - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given 2x + y = 3 ( subtract 2x from both sides )

y = - 2x + 3 ← in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = , thus

y = x + c ← is the partial equation

To find c substitute (5, 4) into the partial equation

4 = + c ⇒ c =

y = x + ← in slope- intercept form

Multiply through by 2

2y = x + 3 ( subtract 2y from both sides )

0 = x - 2y + 3 ( subtract 3 from both sides )

- 3 = x - 2y , that is

x - 2y = - 3 ← in standard form

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.