Sam has a collection of yellow and red cards. Yellow cards are worth 3 points and red cards are worth 5 points. He has at most 15 cards, totaling at least 45 points.
This can be modeled by the following system.

y + r < 15
3y + 5r > 45

Graph the system. Then use the graph to determine which combination is a
solution.
1. 3 yellow and 9 red
2. 6 yellow and 4 red
3. 9 yellow and 3 red
4. 12 yellow and 8 red

1.

1. 3 yellow and 9 red

Step-by-step explanation:

In the picture attached, the system is represented. The darker area shows all the points that are a solution to the system of inequalities.

The combinations can be rewritten as a coordinate pair, as follows:

1. 3 yellow and 9 red  -> (9,3)

2. 6 yellow and 4 red  -> (4,6)

3. 9 yellow and 3 red  -> (3,9)

4. 12 yellow and 8 red -> (8,12)

As we can see in the picture, only the first option is a solution.

its the fourth option

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !