Find the area of the kite

33 cm²

Step-by-step explanation:

Kite = 2 small Δs + 2 big Δs

Area of 1 small Δ

= 1/2 × b × h

= 1/2 × 3 cm × 2 cm

= 3 cm²

Area of 2 small Δs

= 3 cm² × 2

= 6 cm²

Area of 1 big Δ

= 1/2 × b × h

= 1/2 × 3 cm × 9 cm

= 13.5 cm²

Area of 2 big Δs

= 13.5 cm² × 2

= 27 cm²

Area of 2 small Δs + Area of 2 big Δs

= 6 cm² + 27 cm²

= 33 cm²

A) 33 units²

Step-by-step explanation:

A = d₁ₓd₂/2

d₁ = 9 + 2 = 11 units

d₂ = 2ₓ3 = 6 units

a = 11ₓ6/2 = 66/2 = 33 units²

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>