Find the area of the right triangle. If necessary, round to the nearest tenth. A right triangle with side 9 meters and hypotenuse of 18 meters.
a.
15.6 m
b.
70.2 m
c.
42.6 m
d.
243 m

b

Step-by-step explanation:

Let's find the area of the adjacent side.

Applying Pythagoras' Theorem,

(adjacent side)²= 18² -9²

adjacent side

adjacent side= 15.588 m (5 s.f.)

Area of triangle= ½ ×base ×height

Area of traingle

The nearest answer is B.

*If you rounded of to the nearest tenth for the adjacent side first then use the formula for area of traingle, the result would be exactly 70.2 m.

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.