A car accelerates uniformly from 36 km/h to 72 km/h in 2 seconds. Calculate :a. The acceleration of the car b. The distance covered by the car in that time.

(a) The acceleration of the car is 5 m/s²

(b) The distance covered by the car in that time is 30 m

Step-by-step explanation:

Given;

initial velocity of the car, u = 36 km/h = 10 m/s

final velocity of the car, v = 72 km/h = 20 m/s

time for the motion, t = 2 seconds

(a) .The acceleration of the car;

v = u + at

(b) The distance covered by the car in that time

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