A student stands 20 m away from the foot of a tree and observes that the angle of elevation of the top of the tree, measured from a table 1.5 m above the ground, is 34°28'. Calculate the height of the tree to
the nearest metre.

Height of tree is 15 m.

Step-by-step explanation:

Given that student is 20 m away from the foot of tree.

and table is 1.5 m above the ground.

The angle of elevation is: 34°28'

Please refer to the attached image. The given situation can be mapped to a right angled triangle as shown in the image.

AB = CP = 20 m

CA = PB = 1.5 m

= 34°28' = 34.46°

To find TB = ?

we can use trigonometric function tangent to find TP in right angled

Now, adding PB to TP will give us the height of tree, TB

Now, height of tree TB = TP + PB

TB = 13.72 + 1.5 = 15.22 15 m

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

answer: what is the question you're trying to ask?

step-by-step explanation: