P(x) has factors (x-2), (x+1), and (x-3). Decide if there is only one polynomial that has these factors. Justify your conclusions

P(x)= x³ +2x² -5x -6

It's only the above polynomial that have the factors (x-2), (x+1), and (x-3).

Step-by-step explanation:

P(x) has factors of (x-2), (x+1), and (x-3)

Let's determine the polynomial p(x)

(x-2) (x+1) (x-3)= (x² +x-2x-2)(x-3)

(x-2)(x+1)(x-3)= (x²-x-2)(x+3)

(x²-x-2)(x+3)= x³ + 3x² -x² -3x -2x -6

(x²-x-2)(x+3)= x³ +2x² -5x -6

P(x)= x³ +2x² -5x -6

As we can see the polynomial p(x) was gotten from the multiplication of the the three factors.

So it's only the polynomial that has these factors.

The polynomial that has the factors

(x-2), (x+1), and (x-3) is polynomial p(x) only.

answer: no, but if it does it's a obvious pattern.

step-by-step explanation:

sorry

step-by-step explanation:

sorry, but im pretty sure its a now that i look at it