Each point on the edge of a circle is equidistant from the center of the circle. The center of a circle is located at (6, 3). Which point on the y-axis could be on the edge of the circle if the distance from the center of the circle to the edge is 10 units? (0, –1) (0, 1) (0, 5) (0, –5)

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

8/k

step-by-step explanation:

t

step-by-step explanation:

ever thing time 1 is a multiply by 1 it get