Brainliest !A passenger train and a freight train leave at the same time from stations that are 270 km apart. The trains are travelling toward each other, and the rate of the passenger train is twice the rate of the freight train. If the trains pass each other in three hours, what is the rate of each train?

Passenger train 60 km/h.

Freight train 30 km/h.

Step-by-step explanation:

Let the rate of the freight train be x  km / hr the  passenger train's rate is 2x km/hr.

The combined speed = 3x km/hr, so we have the equation

speed = distance . / time

3x = 270 / 3

9x = 270

x = 30 km/h.

need more information

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)