What is the solution to the equation Two-thirds x + 1 = one-sixth x minus 7? x = negative 16 x = negative 4 x = 4 x = 16

x = -16

Step-by-step explanation:

Step 1: Write out equation

2/3x + 1 = 1/6x - 7

Step 2: Subtract 1/6x on both sides

1/2x + 1 = -7

Step 3: Subtract 1 on both sides

1/2x = -8

Step 4: Multiply 2 on both sides

x = -16

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.