The perimeter (distance around the triangle) of a triangular lot is 73 meters with Sides A, B, and C. Side A is 16 meters, Side B is twice the length of Side C. Find the length of Side C.

Brainliest please

Step-by-step explanation:

perimeter is to add all sides

73m= 16+B+C

{ use algebra}

C is a, B is twice C, hence 2a

a+2a(+16)=73

3a=73-16= 57

3a=57, divide

a= 19

B=19×2= 38m

C=19m

C is 19m

C = 19 m

Step-by-step explanation:

Side B is twice the length of Side C.

B = 2C (I)

Perimeter = 73 m

A + B + C = 73

A + 2C + C = 73  {from (I)}

16 + 3C = 73

3C = 73 - 16

3C = 57

C = 57/3

C = 19 m

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

step-by-step explanation:

the true ones are a b and d