Which statement best describes Cheryl's commute? A. Cheryl accelerated to 65 mph, made a stop for 5.5 minutes, and then decelerated to 45 mph. B. Cheryl drove at a speed of 65 mph for 1 minute, drove at a constant speed for 5.5 minutes, and then drove at a speed of 45 mph for 2.5 minutes. C. Cheryl accelerated to 65 mph, drove at a constant speed for 5.5 minutes, and then decelerated to 45 mph. D. Cheryl drove at a speed of 65 mph for 1 minute, made a stop for 5.5 minutes, and then drove at a speed of 45 mph for 2.5 minutes.

C. Cheryl accelerated to 65 mph, drove at a constant speed for 5.5 minutes, and then decelerated to 45 mph.  

Step-by-step explanation:

Assume the graph of Cheryl's commute was like the one below.

We see that she started at 0 mph.  

One minute later, she was up to 65 mph, so she had accelerated (increased her speed).

At 6.5 min (5,5 min later) her speed was still 65 mph, so she was driving at a constant speed.

Over the next 2.5 min, her speed dropped to 45 mph, so she was decelerating.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

111

step-by-step explanation: