3 What is the y-coordinate of the point that divides the
directed line segment from J to k into a ratio of 5:1?
2
AK (7.2)
1
y =
m
m+
-)(x2 - wa) + v
2 3 4 5 6 7 8 9 10 11 x
-11
-2
-3
-4
-5
-8
0-5
0 0
O 6
ibd
-10
J (1,-10)

0

Step-by-step explanation:

Given the points J (1,-10) and K (7, 2)

From the section formula

The y-coordinates of the point that divides the directed line segment from J to K into a ratio of 5:1 is obtained using the formula:

The y-coordinates of the point that divides the directed line segment from J to K into a ratio of 5:1 is 0.

false

step-by-step explanation:

whenever we assume a point on a plane then according to geometry it will definitely have 2 dimensions and if it assumed in space then it will have 3 dimensions.

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!