Line segment AB was dilated to create line segment A'B' using the dilation rule DQ,0.15. Point Q is the center of dilation. Line segment A B is dilated to create smaller line segment A prime B prime. The length of Q A prime is 2.4. The length of A prime A is x. What is x, the distance between points A and A'? 2.4 units 4.8 units 13.6 units 14.4 units

13.6 units

Step-by-step explanation:

Given the following :

Dilation rule : DQ, 0.15

The dilation factor is 0.15

Distance between Q and A' = 2.4

To calculate the distance 'x' between A and A'

The entire length of the side is calculated, that is, A to Q(center of dilation)

Length of A to Q = (Distance A' to Q) / dilation factor

Length of A to Q = 2.4 / 0.15 = 16

Distance (A to A') = x ;

Length AQ - length A'Q

16 - 2.4 = 13.6 units

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

1,150 give brainliest

step-by-step explanation

2r= 2300

r =1150