Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7, 2), and is parallel to the graph x + 3y = -5. Pls help ASAP btw, the answer isn’t -12/19 or 12/19

Step-by-step explanation:

Given

Point: (-7,2)

x + 3y = -5

Required

Find B- - A in Ax + By = 3

To start with; we need to calculate the slope of x + 3y = -5

Subtract x from both sides

Divide both sides by 3

The slope of the line is the coefficient of x

Slope =

The question says line Ax + By = 3 is parallel to line x + 3y = -5; This means that they have the same slope of

Having calculated the slope, next is to calculate the equation of the line using the following formula;

Where m is the slope; m = ;

Substitute these values in the formula above; the formula becomes

Cross Multiply

Open brackets

Add x to both sides

Add 6 to both sides

Multipby both sides by -3

Comparing the above to Ax + By = 3

the line of

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²