Pls help me with trig! i would rlly appreciate it

sin theta = 4 sqrt(2) / 9

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp/ hypotenuse

We need to find the opposite side using Pythagorean theorem

a^2 + b^2 = c^2

b^2 = c^2 - a^2

b = sqrt( c^2 - a^2)

b = sqrt(9^2 - 7^2) = sqrt(32) = 4 sqrt(2)

sin theta =b/c

sin theta = 4 sqrt(2) / 9

hi there!

question 1 answer: p/q can be terminating when q = 5^m * 2^n

question 2 answer: -1 and -1

question 3 answer: -4

question 4 answer: 5/12

hope this : )