Write an equation, in standard form, for the line that passes through the points (-1, -4) and (1, 6).

Step-by-step explanation:

The equation of a line is expressed as y = mx+c where m is the slope and c is the intercept.

m = Δy/Δx = y₂-y₁/x₂-x₁

Given two points (-1, -4) and (1, 6) with x₁= -1, x₂ = 1, y₁  = -4 and y₂ = 6

m = 6-(-1)/1-(-1)

m = 7/2

To get  c, we will substoute the slope and any of the point given into the equation of a line as shown;

Using tyhe point (1, 6) and m = 7/2

6 = 7/2(1)+c

6 = 7/2 + c

c = 6-7/2

c = 5/2

The equation of the line will be y = 7/2 x + 5/2

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47