Imagine you have a very long belt. Well, extremely long, really … in fact, it’s just long enough that it can wrap snugly around the circumference of our entire planet. (For the sake of simplicity, let’s suppose Earth is perfectly round, with no mountains, oceans, or other barriers in the way of the belt.) Naturally, you’re very proud of your belt. But then your brother, Peter, shows up—and to your disgruntlement, he produces a belt that’s just a bit longer than yours. He brags his belt is longer by exactly his height: 6 feet. If Peter were also to wrap his belt around the circumference of Earth, how far above the surface could he suspend the belt if he pulled it tautly and uniformly?

H = 0.95 feet

Step-by-step explanation:

The circumference of Earth = 2πR

My belt = 2πR    (Where R is the radius of the Earth)

Peter's belt = 2πR+6

We have to find the Height "h" so the radius of the circle for Peter's belt becomes R+h So the expression becomes 2π(R+h)

But we already know,

Peter's belt = 2πR+6

So,

2πR+6 = 2π(R+H)

2πR + 6 = 2πR + 2πH

Subtracting 2πR to both sides

=> 6 = 2πH

OR

=> H = 6/2π

=> H = 3/π

Where π = 3.14

=> H = 0.95 feet

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: