A) (Triangle)ABC, given that AB = 16 cm, BC = 63 cm and AC = 65 cm how do we find if it is a right angled

Δ ABC is right angled

Step-by-step explanation:

If the triangle is right then the longest side squared will equal the sum of the squares on the other 2 sides.

longest side = 65, then

65² = 4225

16² + 63² = 256 + 3969 = 4225

Since 65² = 16² + 63² then Δ ABC is right

We can know if it is a right angled triangle by using the Pythagoras theorem ( a²+b²=c²)

Step-by-step explanation:

To identify, we can take the largest length of the triangle as hypotanuse( that is, AC:65) And the rest as base and perpendicular ( 63 and 16 cm)

By applying Pythagoras theorem,

AB²+BC²= AC² ; (63)²+(16)²= (65)²

63² is 3969, 16² is 256… 65² is 4225.

Now, if 63²+16²:65²… then the triangle mentioned is a right angled triangle.

3969+256=4225

LHS = RHS, So, triangle ABC is a right angled triangle as it satisfies the condition of Pythagoras theorem.

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice

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step-by-step explanation: