The lengths of a rectangle have been measured to the nearest tenth of a centimetre they are 87.3cm and 51.8cm what is the upper bound for the area?

Given:

The lengths of the rectangle have been measured to the nearest tenth of a centimetre 87.3 and 51.8  

To find:

the upper bound for the area of the rectangle

Solution:

From given, we have,

The length of the rectangle = l = 87.3 cm

The breadth of the rectangle = b = 51.8 cm

Area of the rectangle = lb = 87.3 × 51.8 = 4522.14 cm²

The upper bound for the area of the rectangle = 4522.14 + 100/2 = 4522.14 + 50 = 4572.14 cm²

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =